1863 United States Senate election in Pennsylvania
(Redirected from United States Senate election in Pennsylvania, 1863)
The 1863 United States Senate election in Pennsylvania was held on January 13, 1863. Charles Buckalew was elected by the Pennsylvania General Assembly to the United States Senate.[1]
Results
editThe Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on January 13, 1863, to elect a Senator to serve the term beginning on March 4, 1863. The results of the vote of both houses combined are as follows:
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Charles R. Buckalew | 67 | 50.38 | |
| Republican | Simon Cameron | 65 | 48.87 | |
| Republican | William D. Kelley | 1 | 0.75 | |
| Totals | 133 | 100.00% | ||
See also
editReferences
edit- ^ a b "U.S. Senate Election - 13 January 1863" (PDF). Wilkes University. Retrieved December 23, 2012.
- ^ "PA US Senate - 1863". OurCampaigns. Retrieved December 22, 2012.