The 1840 United States presidential election in Virginia took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.
 | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
 County Results
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
Virginia voted for the Democratic candidate, incumbent President Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren narrowly won Virginia by a margin of 1.3%, or 1,120 votes.
Results
edit| 1840 United States presidential election in Virginia[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren (inc.) | 43,757 | 50.65% | 23 | |
| Whig | William Henry Harrison | 42,637 | 49.35% | 0 | |
| Totals | 86,394 | 100.0% | 23 | ||
References
edit- ^ "1840 Presidential General Election Results - Virginia". U.S. Election Atlas. Archived from the original on June 19, 2015. Retrieved April 12, 2013.